In this case, since the dilution processes are characterized by the decrease of the original stock solution by holding the moles constant and therefore modify the volume, for the described dilution we can write:
Whereas we are asked to compute the volume of the original solution; thus, we can solve for it as shown below:
1: C- Vf= MfVi/Mi
3: B- Add 1.5 mL of 4.00 M H2SO4 to 10.5 mL of water to get 12 mL of 0.50 M H2SO4.
"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."