The slope of tangent to the curve is simply dy/dx of the curve.By differentiating the curve y w.r.t x we will get the equation of the slope and after that we have to substitute the values of x and y in the new equation that is 1 and 11 respectively.
y=4x^3 - 3x^2 + 10
dy/dx = 12x^2 -6x (d(x^n)/dx=n.x^n-1)
So substituting the values.
dy/dx= 12(1)^2 - 6(1)
dy/dx = 6
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