Ithink the answer is d but i'm not sure if it is correct

1s2 2s2 2p6 3s2 3p6 4s2

A) 1s2 2s1

The alkali metals have one lone outer S electron, because of this we can clearly see that the answer is 1s2 2s1

D

Step-by-step explanation:

28+42=70

14*(2+3)=14*5=70

7*(4+6)=7*10=70

I believe the answer is A.

i think its gonna be c, but im not sure,

Option d, 1s2 2s2 2p6 3s2 3p6 4s2

Explanation:

Alkaline earth metals belong to group 2 of the periodic table. Elements belonging to group 2 are beryllium, magnesium, calcium, strontium and barium and radium.

Alkaline earth metals have 2 valence electrons and these two electrons are filled in outermost s sub shell.

General electronic configuration of alkaline earth metal: ns^2

In ionized state, number of electrons in s sub shell will not be 2.

Among the given, only 1s2 2s2 2p6 3s2 3p6 4s2, has 2 electrons in s sub shell. So, it an electronic configuration of neutral alkaline earth metal.

The correct answer is C) The Roman Catholic Church centralized authority in the Pope, while the Eastern Orthodox Church shared power between the emperor and the patriarch.

The statement that correctly compares the leadership of the Roman Catholic to and the Eastern Orthodox Churches is "The Roman Catholic Church centralized authority in the Pope, while the Eastern Orthodox Church shared power between the emperor and the patriarch."

For Roman Catholics followers, the "heart" of their Church is the Vatican City, in Rome, where the Pope lives and has its offices. All the authority of the Catholic Church relies on the Pope, who is the maximum figure because Catholics believe that he is the vicar of Christ, the representant of Jesus Christ on Earth. In the case of the Eastern Orthodox Church, the authority is shared between the two most important figures for the Orthodox: the patriarch and the emperor.