Abcd and pqrs are rectangles o is the centre of both rectangles ac is a straight line passing through p, o and s bd is a straight line passing through q, o and s pq=8cm and qr=2cm the perimeter of rectangle abcd is 60cm work out the length of ab an the length of bc

10x - 8

Step-by-step explanation:

The perimeter of these can be found by adding length and width and then multiplying by two. 

Rectangle A: (with all of the variables already doubled)

2x + 16 + 2x - 2 

2x + 2x + 16 - 2

4x + 14

So rectangle A's perimeter is 4x + 14.

Rectangle B: (Still with all the variables already doubled)

8x + 10 + 6x - 4

8x + 6x + 10 - 4

14x + 6

So rectangle B's perimeter is 14x + 6

And now to subtract the two.

(7x + 3) - (4x + 14)

14x + 6 - 4x - 14

14x - 4x + 6 - 14

Perimeter of big rectangle = 38 units

Step-by-step explanation:

Let the sides of rectangle (1) = a and c cm

Sides of rectangle (2) = b and c cm

Sides of rectangle (3) = b and d cm

Sides of rectangle (4) = a and d cm

Perimeter of (1) = 2(length + width)

2(a + c) = 10

a + c = 5 ---------(1)

Perimeter of (2) = 2(b + c)

2(b + c) = 20

b + c = 10 -------(2)

Perimeter of (3) =2(b + d)

2(b + d) = 28

b + d = 14 --------(3)

Perimeter of (4) = 2(a + d)

2(a + d) = 18                      

a + d = 9 -------(4)

Since perimeter of the big rectangle = 2(a + b + c + d)

By adding equations (1) + (2) + (3) + (4),

(a + c) + (b + c) + (b + d) + (a + d) = 5 + 10 + 14 + 9

2(a + b + c + d) = 38

Therefore, perimeter of the rectangle ABCD = 38 units

the other person was correct. 10x - 8.

The perimeter of the big rectangle is 38 cm

Step-by-step explanation:

Rectangle 1 and rectangle 2 share the same width, let their width be a cm while Rectangle 3 and rectangle 4 share the same width, let their width be b cm

Rectangle 1 and rectangle 3 share the same length, let their length be x cm while Rectangle 2 and rectangle 4 share the same length, let their length be y cm

The perimeter of a rectangle = 2(length + breadth).

For rectangle 1:

Perimeter = 2(a + x) = 10

a + x = 5            1)

For rectangle 2:

Perimeter = 2(a + y) = 20

a + y = 10          2)

For rectangle 3:

Perimeter = 2(b + x) = 28

b + x = 14         3)

For rectangle 4:

Perimeter = 2(b + y) = 18

b + y = 9         4)

Adding equations 1, 2, 3 and 4 gives:

a + x + a + y + b + x + b + y = 5 + 10 + 14 + 9

a + a + b + b + x + x + y + y  =38

2a + 2b + 2x + 2y = 38

2((a + b) + (x + y)) = 38

For the big rectangle, let its width = c = a + b and its length be d = x + y

The perimeter of the big rectangle = 2 (c + d)

Therefore:

2((a + b) + (x + y)) = 38

2(c + d) = 38 cm = The perimeter of the big rectangle

The perimeter of the big rectangle is 38 cm

To find the perimeter of a rectangle use this formula:  2a + 2b

a is one side

b is the other side

Hope this helps :)  Brainliest is greatly appreciated.

Given : Abcd and pqrs are rectangles o is the centre of both rectangles ac is a straight line passing through p, o and r .  bd is a straight line passing through q, o and s pq=8cm and qr=2cm

To find : length of ab and the length of bc if perimeter of rectangle abcd is 60cm

Solution:

ΔPQR ≈ ΔABC

as PR  & AC are same line

& PQ ║ AB   &  QR ║ BC

=> PQ / AB  = QR/BC

=> 8/AB  = 2/BC

=> AB = 4BC

Perimeter of ABCD rectangle = 2(AB + BC)

= 2( 4BC + BC)

= 10BC

Perimeter = 60 cm

=> 10BC = 60

=> BC = 6  cm

AB = 4BC = 24 cm

Length of AB = 24 cm & length of BC = 6 cm

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