The 25 students in cs 70 have a strange way of picking a study group. each person is given a distinct number 1 through 25 based on random chance, and participants may form a group as cs 70, fall 2019, hw 7 long of the sum of their numbers is at most 162. (the tas are afraid of the number 162 for some how many different study groups are possible? that is, how many different subsets of students are there, which are allowable under the ranking rule? (hint: 162 = [( i)- 11/2) (b) uc berkeley is forming a new, n-person robotics team. there are 2n interested students n mechanical engineers and n programmers. (assume that no student is both a mechanical engineer and a programmer.) find the number of distinct n-person teams. (c) suppose that all robotics teams must also name a team captain who is a mechanical engineer. find the number of ways to pick an n-person team with a mechanical engineer as the captain.
4. picking teams (b) since each person on the team is unique we can simply ignore the fact that there are 2 professions. the amount of permutation of 2n students is 2n! , but since we are only picking n of them we will not need to pick anymore students after having n students on the team. hence the the amount of permutation of 2n students but only picking n student is (2n) (2n-1) (2n-2) (2n- (n) which is equal to 2 = 20). since the team is unordered, so a team consisting of student a, b, c is the same team consisting b, a, c we will need to divide the total amount of permutation by the number of orders. thus the total combination of 2n students to make a team of n student is (c) if a mechanical engineer is taken out of the pool of mechanical engineers, there will be n-1 of them left thus the total amount of students left to arrange is 2n - 1 students. applying the same process as part (b), we have 2n-1-11)1 = (n-1)! diving 1): = 2n-1). diving the total amount of permutation by the number of orders, we have 21 (12- ways.
Well the captain of the Nautilus is Captain Nemo. Jules Verne never revealed his real real name. So, the best answer is Captain Nemo.
Explanation: I think
M. de Tréville is the name of the captain in the novel The three musketeers
1. c. Richelieu's Guards
2. c. He complained to the Queen.
3. a. D'Artagnan's bravery and skill in defeating Richelieu's guards at the Convent.
4. b. Porthos
5. b. horse
6. b. buttercup
7. c. Provincial
8. d. Athos
9. b. swordsmanship, horsemanship, and first aid
10. c. Aramis dropped and stepped on a handkerchief, and D'Artagnan picked it up to give it to him.
The story centres around D'Artagnan who goes after Man from Meung. Athos is cross with D'Artagnan. This results in a conflict in between the two. D'Artagnan cannot find his target on the street. This causes a constant clash between the two.
a Those are the answers because i read a of these books
Hi! I liked your story. It was pretty hard to follow in some parts including the beginning. The beginning needs more information about the characters. I'm not sure who Dannie and Quinn are. Also, the dialog was a little hard to follow because you didn't mention who was talking. Especially in the last section about how many zeros there are in billions. I'm not sure who was talking and it seemed very out of place. I think you can do with out that piece of dialog.
Hope it helps! :)
Hope this helps.
1. is C. Richelieu's guards
2. is C. he complained to the king
3. is A. D'Artagnan's bravery and skill in defeating Richelieu's guards at the Convent.
4. is D. D’artagnan
5. is B. horse
6. is buttercup
Stopping Distance= 197.82 m
Stopping time= 1.403 s
Given that:initial velocity, u=282 acceleration, a= -201 final velocity, v= 0 ∵ the body comes to the rest finally
To find:Stopping time, tstopping distance, s
From the given and asked data we identify the required equations of motion.
For calculating the stopping time: ⇒
For calculating the stopping distance:
putting the respective values
The sled needed a distance of 92.22 m and a time of 1.40 s to stop.
The relationship between velocities and time is described by this equation: , where is the final velocity, is the initial velocity, the acceleration, and is the time during such acceleration is applied.
Solving the equation for the time, and applying to the case: , where because the sled is totally stopped, is the velocity of the sled before braking and, is negative because the deceleration applied by the brakes.
In the other hand, the equation that describes the distance in term of velocities and acceleration:, where is the distance traveled, is the initial velocity, the time of the process and, is the acceleration of the process.
Then for this case the relationship becomes: .
Note that the acceleration is negative because is a braking process.