Mathematics, 08.11.2019 05:31, stranger123

Aproperty map is drawn at a scale of 1: 1000. calculate the corresponding actual distance if the distance between two points on the map is: 1 cm plz me

Answers: 3

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Answers

The correct answer was given: misaki2002

10 m

Step-by-step explanation:

Given

Scaling ratio 1:1000

i.e. one unit in map is equal to 1000 unit in actual distance

therefore if the distance between two points is 1 cm in map then

it is 1000 cm in reality

The correct answer was given: duxks

2500 cm

Step-by-step explanation:

The complete question is in the attachment.

The scale of the map is 1:1000

This means that, 1 cm on the map represents 1000 cm on the ground(actual distance).

To find the actual distance between two points that are 2.5 cm on the map, we just have to multiply by 1000 to get:

2.5*1000=2500

Therefore the corresponding actual distance is 2500 cm

Aproperty map is drawn at a scale of 1: 1000. calculate the corresponding actual distance if the dis

The correct answer was given: jfy3341

The corresponding actual distance if the distance between two points on the map is 2.5 cm is 25 m

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Further explanation

Let us recall some important formulas about drawing at scale

$\texttt{Scale = Map Distance} \div \texttt{Ground Distance}$

$\texttt{Scale}^2 \texttt{ = Map Area} \div \texttt{Ground Area}$

Let us tackle the problem !

$\texttt{ }$

Assume the complete question as follows:

A property map is drawn at a scale of 1:1000. Calculate the corresponding actual distance if the distance between two points on the map is 2.5 cm !

$\texttt{ }$

A property map is drawn at a scale of 1 : 1000.

$\texttt{Scale} = \texttt{1 : 1000}$

The distance between two points on the map is 2.5 cm

$\texttt{Scale = Distance on map (figure)} \div \texttt{Actual Distance}$

$1 : 1000 = 2.5 \div \texttt{Actual Distance}$

$1 \times \texttt{Actual Distance} = 1000 \times 2.5$

$\texttt{Actual Distance} = 2500 \texttt{ cm}$

$\texttt{Actual Distance} = 2500 \div 100 \texttt{ m}$

$\texttt{Actual Distance} = 25 \texttt{ m}$

$\texttt{ }$

Conclusion:

The corresponding actual distance if the distance between two points on the map is 2.5 cm is 25 m

$\texttt{ }$

Learn moreInfinite Number of Solutions : System of Equations : System of Linear equations : Answer details

Grade: Middle School

Subject: Mathematics

Chapter: Percentage

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point , Multiplication , Division , Exponent , PEMDAS , percentange , percent

The correct answer was given: Brain

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!

The correct answer was given: Brain

0.32

step-by-step explanation:

2.24/7