Find the values of a, b, and c in the equation below.

a =

b =

c =

A:4

B:3

C:5

I feel like you should have been given more information than what's been shown to us

a = 12, b = 2, c = 11

Step-by-step explanation:

Using exponent rules we can distribute the exponent of 3 to the xyz.

This results in the numerator now being. This can be simplified to, .

Now divide the numerator by the denominator subtracting the exponents.

Which equals,

So a = 12

b = 2

and

c = 11

a = 12, b = 2, z = 11

Step-by-step explanation:

  (x^5yz^4)^3/(x^3yz)

= (x^15y^3z^12)/(x^3yz)

=  x^12y^2z^11

=> a = 12

=> b = 2

=> z = 11

no se

Step-by-step explanation:

x^12 y^2 z^11

a= 12

b= 2

c= 11

Step-by-step explanation:

On the numerator you distribute the exponent 3 to the other exponents.

I think you multiply the 3 so you would get: x^15 y^3 z^12.

so it looks like x^15 y^3 z^12 / x^3yz

Then you subtract the top exponents from the bottom exponent because when you are dividing you subtract exponents. the exponent for y and z in the denominator is 1

and thats how i got x^12 y^2 and z^11. The exponents are a b and c

I hope that is right