Mathematics, 08.11.2019 06:31, AgarioEdit

What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)?
a.-8
b.-4 c.33 d.49

Answers: 2

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Answers

The correct answer was given: hahahwha

( −4;49)

is the answer

What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)? a.-8b.-4 c.33 d.49

The correct answer was given: nerdywolf2003

Step-by-step explanation:

The answer is D. 49 on EDGE

The correct answer was given: samueltaye

49 just took the unit review

Step-by-step explanation:

The correct answer was given: jakeyywashere

49.

Step-by-step explanation:

We have been a function f(x)=-(x-3)(x+11) . We are asked to find the y-value of vertex of the given function.

Upon multiplying both factors, we will get,

f(x)=-(x*x+11*x-3*x-3*11)

f(x)=-(x^2+11x-3x-33)

f(x)=-(x^2+8x-33)

f(x)=-x^2-8x+33

Now, we will use $\frac{-b}{2a}$ formula to find the x-coordinate of vertex of parabola.

$\frac{--8}{2*-1}$

$\frac{8}{-2}$

Since the x-coordinate of vertex of parabola is , so we will substitute x=-4 in our equation to find y-coordinate of parabola.

f(-4)=-(-4)^2-8(-4)+33

f(-4)=-16+32+33

f(-4)=49

Therefore, the y-coordinate of vertex of the given parabola is 49.

The correct answer was given: freemankellie

Step-by-step explanation:

f(x)=-(x-3)(x+11)

The zeros of the equation are 3 and -11

The vertex is 1/2 way between the two values

(3+-11)/2 = -8/2 = -4

The vertex is at x= -4

We substitute this value into the equation to find the y value

f(x)=-(-4-3)(-4+11)

= -(-7)(7)

=49

The correct answer was given: QueenFlowerCrown98

Step-by-step explanation:

Given

f(x) = - (x - 3)(x + 11)

Find the zeros by setting f(x) = 0, that is

- (x - 3)(x + 11) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x + 11 = 0 ⇒ x = - 11

The vertex lies on the axis of symmetry which is situated at the midpoint of the zeros

$x_{vertex}$ = $\frac{3-11}{2}$ = $\frac{-8}{2}$ = - 4

Substitute x = - 4 into f(x) for y- coordinate of vertex

f(- 4) = -(- 7)(7) = 49 ← y- value of vertex

The correct answer was given: ian1588

Step-by-step explanation:

The given function is f(x)=-(x-3)(x+11) .

We expand to get:

f(x)=-x^2-8x+33

We complete the square to obtain the vertex form as follows:

f(x)=-(x^2+8x)+33

f(x)=-(x^2+8x+16)--16+33

f(x)=-(x^2+8x+16)+16+33

f(x)=-(x+4)^2+49

This function is now of the form:

f(x)=a(x-h)+k , where (h,k)=(-4,49) is the vertex.

The y-value of the vertex is therefore 49

The correct answer was given: asialuv

Step-by-step explanation:

The vertex lies on the axis of symmetry which is situated at the midpoint of the zeros.

Find the zeros by letting f(x) = 0, that is

- (x - 3)(x + 11) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x + 11 = 0 ⇒ x = - 11, thus

$x_{vertex}$ = $\frac{-11+3}{2}$ = $\frac{-8}{2}$ = - 4

Substitute x = - 4 into f(x) for y- value of the vertex

f(- 4) = - (- 4 - 3)(- 4 + 11) = - (- 7)(7) = 49

The correct answer was given: stephliu721

Answ1er:

Step-by-step explanation:

The correct answer was given: bzhsh8282

If we expand the product, we have

f(x)=-(x+3)(x-14)=-x^2+11x+42

The x-coordinate of the vertex is given by

$V_x=-\dfrac{b}{2a}=-\dfrac{11}{-2}=\dfrac{11}{2}$

Plug this value in the equation to find the correspondant y-value:

$f\left(\dfrac{11}{2}\right)=-\left(\dfrac{11}{2}\right)^2+11\left(\dfrac{11}{2}\right)+42=-\dfrac{121}{4}+\dfrac{121}{2}+42$

The correct answer was given: Brain

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this

The correct answer was given: Brain

overpriced

step-by-step explanation:

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What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)?
a.-8
b.-4 c.33 d.49...