Alice Gleason invested $ 16000 at 9 % interest and $ 16000 at 11 % interest
Given, Alice Gleason invested a portion of $32000 at 9% interest and the balance at 11% interest.
We have to find how much did she invest each rate if her total income from both investments was $3200.
Let the 1st part of amount be y, then second part will be $32000 – y.
Where "p" is principal amount
"n" is number of years
"r" is rate of interest
Now, according to given information,
Simple interest for 1st part + simple interest for 2nd part = 3200
Considering to be for 1 year,
She invested $ 16000 at 9 % interest and $ 16000 at 11 % interest
if x = 2 you have to find x to finish the problem
r(0,90)(x,y) . t(-5,0)
∆def to ∆d"e"f"
- rotate 90 counterclockwise degrees
- then translated 5 to the left (x --> x - 5)
answer is the last option