y -1 = 6x ⇔ y = 6x + 1
y - 1 = 3x ⇔ y = 3x + 1
y - 7 = 2x - 6 ⇔ y = 2x - 6 + 7
y = 2x + 1
y - 7 = x - 2 ⇔ y = x - 2 + 7
y = x + 5
Equations cleverly arranged .
Point Q = (0,1)
b factor , not only fits the last equation
In the drawing have engraved points Q and R are tangent linear function appropriate to that point . This graphics solution . y = 3x + 1
We check choice by the system of equations , where substitute wartoćsi points Q and R to the model equations linear function
The result of equations confirmed our choice Answer b
Figure I'll add soon
slope(m) = (7-1) / (2-0) = 6/2 = 3
y = mx + b
slope(m) = 3
use either of ur points...(0,1)x = 0 and y = 1
now sub and find b, the y int
1 = 3(0) + b
1 = b
so ur equation is : y = 3x + 1or 3x - y = -1
B y - 1 = 3x
its B y– 1 = 3x
y – 1 = 3x
since Q is (0,1) that would make 1 the y-intercept.
using a formula to find the slope we end up with 3.
1 is a negative because when moved to the other side it must be positive.
y – 1 = 3x
The slope of this line is given by
Where m is the slope
(x_1, y_1) is the first point, (0,1), and
(x_2,y_2) is the second point (2,7)
Substituting, we get:
The point slope form of a line is given by
Substituting , we get:
2nd option is right.
Hello : let
the slope is : (YR - YQ)/(XR -XQ)
(7-1)/(2-0) = 3
an equation is : y=ax+b a is a slope
y = 3X +b
the line through point Q(0,1) :
b = 1
the equation is : y =3x+1
m = y2 - y1 / x2 - x1
m = 7 - 1 / 2 - 0
m = 6 / 2
m = 3
The slope of the line is 3.
Substitute the slope and either given coordinate into the equation of a line:
y - y1 = m(x - x1)
Using the coordinate (2, 7):
y - 7 = 3(x - 2)
y - 7 = 3x - 6
Add 7 to both sides of the equation.
y = 3x + 1
Solution: y = 3x + 1
that equation is:
now we implement our given coordinates.
let Q be point 1 and R be point 2
y - 1 = 6/2(x - 0)
y - 1 = 3x
Answer is b.
207/8 is the right
i think the correct option is the second option.