Which is the completely factored form of 12x^3 – 60x2 + 4x – 20?

4(3x^2 – 1)(x – 5)
4x(3x^2 + 1)(x – 5)
4x(3x^2 – 1)(x + 5)
4(3x^2 + 1)(x – 5)

x (2 x^2 + 4 x - 1)

Step-by-step explanation:

Factor the following:

2 x^3 + 4 x^2 - x

Factor x out of 2 x^3 + 4 x^2 - x:

 x (2 x^2 + 4 x - 1)

(12x²+4)(x-5)

Step-by-step explanation:

To factor the expression factor by grouping.

(12x³ - 60x²) + (4x - 20)

12x²(x - 5) 4(x-5)

(12x²+4)(x-5)

2 ( x ^3 + 2 x^ 2 − 2 )

Step-by-step explanation:

Factor  2  out of  

2 x^ 3 + 4 x^ 2 − 4 .

4(x-5)(3x² +1)

Step-by-step:

Add and subtract the second term to the expression and factor by grouping.

Hope this helps!

For this case we must factor the following expression:

It is observed that each of the three terms has a common factor of "2":

The expression within parentheses can not be factored with rational numbers.

Finally the result is:

I think it's:

x(2x^2+4x-1)

the answer should be 2x^3+2x+2x-x

The correct answer is yes. just distribute 12 to all within first set then 6 to all in 2nd set then add like terms

x(2x^2+4x-1)

Step-by-step explanation:

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

35 is an outlier

step-by-step explanation: