Find the sum of the first 50 terms of the sequence below.
an = 3n + 2

it’s 3925

Step-by-step explanation:

82.5 (assuming it is an arithmetic sequence)

Step-by-step explanation:

-450

Step-by-step explanation:

Say the first number is x to get the idea.

The first 150 terms are 150x - 5 * 150

15x - 750

300 - 750 = -450

2,322,775

Step-by-step explanation:

Given a1 = 4 and ai =ai-1 +11

when i = 2

a2 = a2-1+11

a2 = a1+11

a2 = 4+11

a2 = 15

when i = 3

a3 = a2+11

a3 = 15+11

a3 = 26

The sequence formed by a1, a2, a3... is am arithmetic sequence as shown;

4, 15, 26...

Sum of nth term of an arithmetic sequence = n/2{2a+(n-1)d}

a is the first term = 4

d is the common difference = 15-4 = 26-15 = 11

n is the number of terms.

Since we are to find the sum of the first 650 terms in the sequence, n = 650

S650 = 650/2{2(4)+(650-1)11}

S650 = 325{8+(649)11}

S650 = 325(8+7,139)

S650 = 325×7147

S650 = 2,322,775

3925

Step-by-step explanation:

this  arithmetic  sequence  the first term is : A1 = 3(1)+2=5

and common difference is  r = 3

the sum of the first 50 terms  is : S50 = 50/2(A1  + A50)

A50 = 3(50)+2 = 152

S50 = 50/2(5  + 152)= 3925

4600

Step-by-step explanation:

STEP 1: Determine type of progression

Since d1 = d2, it is Arithmetic progression, with a common difference of 4

STEP 2: Evaluate the sum

82.5

Step-by-step explanation:

hope this is correct

in 1st sequence put 1 instead of n

i.e

a1=3×1+2

=3+2

=5

Step-by-step explanation:

now do all the 50 terms by placing 1 to 50 instead of n

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest

answer: rolling a number cube and flipping a coin.

step-by-step explanation: