a relation is plotted as a linear function on the coordinate plane starting at point c (0,−1)(0,−1) and ending at point d (2,−11)(2,−11) . what is the rate of change for the linear function and what is its initial value? select from the drop-down menus to correctly complete the statements. the rate of change is -11, -5, 0, 5.and the initial value is -11, -2, -1, 0.
slope = (y2 - y1)/(x2 - x1) = (-11 - (-1))/(2 - 0) = -10/2 = -5
I'm not sure what is meant by initial value, but maybe you are looking for the y-intercept of the line.
The y-intercept is the point where the line crosses the y axis, so where x = 0. You have that because your line passes through the point (0, -1). When x = 0, y = -1.
given that triangle abc is transformed two times to get triangle
first abc is transformed in to a'b'c' as follows:
the coordinates of a are (1,-1) and transformed into a'(-1,1)
similarly b (4,-2) became b'(-4,2) and
c(7,-2) became c'(-7,2)
i.e. (x,y) becomes (-x,-y)
this is nothing but reflection about a point here origin.
thus first transformation is reflection on the origin.
next is exactly shifting 3 units down
the correct answer to your question is a. 4^4
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a relation is plotted as a linear function on the coordinate plane starting at po...