Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.00×104 pa . assume that air is an ideal gas, with γ=1.40. (this rate of cooling for dry, rising air, corresponding to roughly 1 ∘c per 100 m of altitude, is called the dry adiabatic lapse rate.)
Let's use the equation that relate the temperatures and volumes of an adiabatic process in a ideal gas.
Now, let's use the ideal gas equation to the initial and the final state:
Let's recall that the term nR is a constant. That is why we can match these equations.
We can find a relation between the volumes of the initial and the final state.
Combining this equation with the first equation we have:
Now, we just need to solve this equation for T₂.
Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.
Finally, T2 will be:
answer would be letter choice (a), a ball resting on a shelf. would be another example of potential energy > stored energy > not moving.
a ball spinning on a finger > kinetic energy > moving energy
a ball rolling on the ground > kinetic energy > moving energy
a ball flying through the air > kinetic energy > moving energy
hope that : )