A3.7kg block on a horizontal frictionless surface is attached to a spring whose force constant is 450 n/m. the block is pulled from equilibrium position at x=0m to a displacement x=+0.080m and is released from rest. the block then executes simple harmonic motion along the x-axis. the maximum elastic potential energy of the system is closest to? ( 1.4 j) i just need to understand how to get there. show the equations used
m = 3.7 kg
K = 450 N/m
X= 0.08 m
We know that spring stored potential energy(U) and this potential energy given as
By putting the values
b) returns freshwater to the earth.
c) returns freshwater to the earth.c) occurs after condensation.
d) returns freshwater to the earth.c) occurs after condensation.d) roughly equal to the amount of evaporation.
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hello, i am papaguy.
i have found an answer to your question but use it as information.
information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.
best of luck!