Δy = 1.40 m
v₀ = 0 m/s
a = 1.67 m/s²
Δy = v₀ t + ½ at²
(1.40 m) = (0 m/s) t + ½ (1.67 m/s²) t²
t = 1.29 s
a small object of mass 3.66 g and charge -17.6 µc is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. what are the magnitude and direction of the electric field?
pe = weightxheight = 2000x1000=2,000,000joules
it’s the bonus question. i want to have an explanation...