Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :
When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :
So, the radius of the resulting electron trajectory is . Hence, this is the required solution.
(a) 5172 V/m
The electric field strength of a uniform field between two parallel plates is given by:
V is the potential difference between the plates
d is the distance between the plates
Here we have
V = 3.00 x 10^3 V
d = 0.580 m
So the electric field strength is
(b) 1.74 x 10^5 m/s
According to the law of conservation of energy, the electric potential energy of the ion is converted into kinetic energy. Therefore we can write:
is the charge of the ion
is the potential difference
is the mass of the ion
v is the final speed of the ion
Solving for v, we find
(c) 0.664 m
When the ion moves into the magnetic field region, the magnetic force acting on it acts as centripetal force.
The magnetic force is:
F = qvB
B = 5.19 x 10^−2 T is the magnetic field strength
v is the speed of the ion, found in the previous part
While the centripetal force is
r is the radius of the circular path
So we can write
and solving for the radius, we find
Alpha and beta radiation can also be deflected by magnetic fields . Just as with electric fields, gamma radiation is not deflected by magnetic fields.
Gamma is NOT deflected by a magnetic field.
Gamma radiation isn't deflected
Hi, Rutherford characterized three types of radioactivity: Alfa, Beta and Gamma.
The principal difference is that the first two are charged particules (+ or -) but the gamma radiation comes from neutral particules.
Magnetic fields have the ability to interact with charged particules (like ions) or with ionizable elements (like the ferritic ones).
Being that said, the gamma radiation won't be deflected by the magnetic field because of its neutrality.
R = 0.584m
Given B = 537G = 537×10-⁴T = 0.054 T
Mass, m = 3.98×10-²⁶ kg, V = 2.00kV = 2000V. q = 1.6×10-¹⁹ C
The radius R of curvature is given by
R = mv/qB
We don't know the value for v the velocity, but we can get the expression for it from energy concepts.
The electric potential energy of the field is equal to the kinetic energy of the ion
qV = 1/2mv²
v² = 2qV/m = 2 ×1.6×10-¹⁹×2000 /(3.98×10-²⁶)
v² = 1.608×10¹⁰
v = sqrt(1.608×10¹⁰)= 126809m/s
So R = 3.98×10-²⁶ × 126809/(1.6×10-¹⁹ × 0.054)
R = 0.584 m
The radius of curvature of the ion's orbit is 0.59 meters
Mass of the 24 Mg ion,
Potential difference, V = 3 kV
Magnetic field, B = 526 G
Charge on single ionized ion,
The radius of the the path traveled by the charge is circular. Its radius is given by :
v is speed of particle.
v can be calculated using conservation of energy as :
So, the radius of curvature of the ion's orbit is 0.59 meters.
they have a negligible mass and they also have a negative charge so they have an association with the magnetic field. Do you remember polar? So electrons are negative and they attract the nucleus which is overall postivie (since protons are positive) so they act as magnetic since they both have an attraction
First, Its magnitude is proportional to the magnitude of the charge.
Second, the magnitude of the force is also proportional
Third, the magnetic force depends on the particle’s
Fourth, we find by experiment that the magnetic force does not have the same direction as the magnetic field but instead is always perpendicular to both and the velocity
So, in a mathematical language this is given by:
So, this is a cross product. Therefore, applying the Right-hand rule:
The answer is:
D. to the left of its velocity.
Explaining this in other words:
"The force is directed into the plane of the paper, so this is the direction of the proton"
scorpions are animals in the order scorpiones, under the class arachnida, which makes them a distant cousin of spiders
pls mark as brainliest.
i don't know that i agree with that but what's the question ?