Aflask containing argon gas is connected to an closed-ended mercury manometer. the closed end is under vacuum. if the mercury level in the closed arm is 230. mm above that in the arm connected to the flask, what is the argon pressure, in torr?

230 torr

Explanation:

Given that

P = 230 mm of Hg

If argon gas and mercury is in equilibrium position then the pressure on the both side will be same .

As we know that

1 torr = 1 mm of Hg

So the pressure of the argon will be 230 torr .

Unit conversion

1 torr = 1 mm of Hg

1 bar = 100 KPa = 10⁵ Pa =  10⁵ N/m² = 0.1 MPa = 0.1 x 10⁶ Pa

Hey there!:

This is a simple question is you know about your units. The pressure exerted by the argon gas is 230 mmHg. Which is a unit of pressure. 1 Torr is approximately equal to 1 mmHg. So the answer is 230 Torr.

Hope that helps!

The correct answer is option c = 230. torr

Explanation:

Hello!

Let's solve this!

First, keep in mind that the conversion from mmHg to torr is:

1mmHg = 1torr

To measure the pressure in a mercury manometer, the height of the mercury is measured and that is the pressure.

In this case, the height is 230mm so the pressure is 230mmHg. Since the conversion is one to one, the answer is 230torr.

Then, we conclude that the correct answer is option c = 230. torr