Part one: a gust of wind blows an apple from a tree.
as the apple falls, the force of gravity on the
apple is 9.39 n downward, and the force of
the wind on the apple is 1.50 n to the right.
what is the magnitude of the net external
force on the apple?
answer in units of n.
part two: what is the direction of the net external force
on the apple (measured from the downward
vertical, so that the angle to the right of
downward is positive)?
answer in units of ◦
The force of gravity on the apple, (downward)
The force of the wind on the apple, (right)
Let F is the magnitude of the net force acting on it. The resultant of two vectors is given by :
F = 9.509 N
So, the direction of the net external force is 9.07 degrees wrt vertical. Hence, this is the required solution.
Part ONE: 9.51 N
Gravitational force exerted on the apple is 9.39 N
Force exerted by the wind on the apple is 1.5 N
Net force on apple is given by’
where W is gravitational force, F is force due to wind and is the angle between the gravitational force and wind force. For this case, hence the equation is re-written as
Then substituting W for 9.39 and F for 1.5 we obtain
The direction of net force is given by
as the apple falls, the force of gravity...