Apply the junction rule at point a in Figure 21.52.

A is 8 and B is 4

Explanation:

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Step-by-step explanation:

The image of the circuit is obtained online and attached to the question.

The junction rule is essentially a law of conservation of current (charges). It applies to electrical circuits at steady state.

It explains that the for any given junction (node in an electrical circuit), the sum of current entering the junction is equal to the sum of current leaving the junction. That is, the net sum of current at any junction is zero.

Current entering a junction is assigned a positive sign and that leaving the junction is assigned a negative sign.

Σ I = 0

From the image of the circuit attached, I₁ is leaving the junction labelled number 1 and I₂ and I₃ are entering the junction.

Hence,

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Hope this Helps!!!

1) At any junction point in a circuit, the sum of all the currents entering the junction must equal the sum of all the currents leaving the junction. Kirchhoff's loop rule is based on the conservation of charge.

The second sentence is wrong. It should be "kirchhoff's junction rule" not "Kirchhoff's loop rule"

2) The sum of the changes in potential around any closed loop of a circuit must equal zero. Kirchhoff's junction rule is based on the conservation of energy.

The second sentence is wrong. It should be "kirchhoff's close loop rule" not "Kirchhoff's junction rule"

A) attached file

B) attached file

C) attached file

D) Kirchhoff’s junction rule states that at any junction, the sum of the altimeter attained moving into and out of that junction are equal.

While

Kirchhoff’s loop rule states that the algebraic sum of the number of lifts used in any closed loop is equal to zero

Explanation:

Given that the lifts are analogous to batteries, and the runs are analogous to resistors. 

So from all the figures. The resistors represent the runs while the lift represents the battery.

Kirchhoff’s junction rule states that at any junction, the sum of the altimeter attained moving into and out of that junction are equal.

While

Kirchhoff’s loop rule states that the algebraic sum of the number of lifts used in any closed loop is equal to zero

Please find the attached file for the sketch

After the junction the current in path A is 8 and the current in path B is 4​

Explanation:

The junction rule states that the total current going into the junction equals the total current going out, so the total current in both paths must equal 12 if there are only two paths

6 + 2 = 8

3 + 4 = 7

8 + 4 = 12

the last one is the only one that adds up to 12

Explanation:

(A) True: It is true.

In junction law, the current entering at a junction is equal to teh current leaving at the junction.

(B) False: It is false.

The kirchhoff's junction law is based on the conservation of charge.

(C) True: It is true.

Energy is used in the circuit.

(D) True: It is true.

It is based on the conservation of charge.

This is the correct question.

Apply the junction rule to the junction labeled with the number1 (at the bottom of the resistor of resistance R_2).

Answer in terms of given quantities,together with the meter readings I_1 and I_2 and the current I_3.

b) Apply the loop rule to loop 2 (the smaller loop on the right).Sum the voltage changes across each circuit element around this loop going in the direction of the arrow. Remember that the current meter is ideal.

Express the voltage drops in terms ofV_b, I_2, I_3, the given resistances, and any other givenquantities.

c) Now apply the loop rule to loop 1(the larger loop spanning the entire circuit). Sum the voltagechanges across each circuit element around this loop going in thedirection of the arrow.

Express the voltage drops in terms ofV_b, I_1, I_3, the given resistances, and any other givenquantities.

Explanation:

a. Junction rule: Kirchhoff current law (KCL)

Then, total current entering a junction equals to current leaving the junction.

Therefore,

i1=i2+i3

b. Apply Kirchoff voltage law ( KVL) to loop 2

Then, sum of voltage in the loop equals to zero.

-i3R3+i2R2=0.

Then,

i2R2=i3R3

c. Apply KVL to the loop 1

-Vb+i1R1+i3R3

Therefore,

Vb=i1R1+i3R3.

The circuit diagram is in the attachment